The 2021 -2024 and Continuing Joke Threads

[SailRN]

Originally Posted by goboatingnow

????. aliens ... , who are the elites. The people I know concerned about AGW are just ordinary joes , especially young people

What is AGW?

[Adelie]

AGW - Anthropogenic Global Warming
MMGW - Man Made Global Warming,
There are some others.

[delmarrey]

Originally Posted by Midnight Son

delmarrey is confusing rich Republicans and rich Dems again/still.🤣😎

I said nothing about political parties! The majority of Elites are the 1%ers. We have a few right here in the Salish Sea dominating our shorelines.

[StuM]

Originally Posted by GordMay

A Republican and a scientist were together, during the last moments of the Titanic ...
The scientist said: "In a hundred years that giant iceberg would melt and contribute in the rising of the sea level."
.

Mustabin a "climate scientist" to say anything so stupid.

[Mirage35]

Okay, not a joke but an amusing question, since we're talking about impact on water levels.

You're in a small boat, in a swimming pool, with a large rock in it. You pick the rock up and drop it in the pool.

Does the water level in the pool go up, go down, or stay the same.

(In my experience, if you ask this of a bunch of engineers after they've had a couple of beers you'll keep them off the streets for the next couple of hours.)

[skipmac]

Originally Posted by AnglaisInHull

Okay, not a joke but an amusing question, since we're talking about impact on water levels.

You're in a small boat, in a swimming pool, with a large rock in it. You pick the rock up and drop it in the pool.

Does the water level in the pool go up, go down, or stay the same.

(In my experience, if you ask this of a bunch of engineers after they've had a couple of beers you'll keep them off the streets for the next couple of hours.)

Depends on the density of the rock. Heavy rock, IE density greater than water then the boat sitting lower displaces more water than the just rock so tossing the rock in the water the level goes down.

Density of the rock lighter than water then the rock will float. In that case I'll have to think about it more carefully but I think the water level would go up but might stay the same.

[Montanan]

Originally Posted by skipmac

Depends on the density of the rock. Heavy rock, IE density greater than water then the boat sitting lower displaces more water than the just rock so tossing the rock in the water the level goes down.

Density of the rock lighter than water then the rock will float. In that case I'll have to think about it more carefully but I think the water level would go up but might stay the same.

Now that is some dense thought and reasoning.

[Lodesman]

Originally Posted by StuM

Mustabin a "climate scientist" to say anything so stupid.

Exactly. But the sheep will buy it, hook, line and sinker.

[IslandHopper]

[Jon Hacking]

Originally Posted by skipmac

Depends on the density of the rock. Heavy rock, IE density greater than water then the boat sitting lower displaces more water than the just rock so tossing the rock in the water the level goes down.

Density of the rock lighter than water then the rock will float. In that case I'll have to think about it more carefully but I think the water level would go up but might stay the same.

Good answer. Since the floating rock is displacing its WEIGHT, not its volume, this is the same as when it was in the boat, so the water level of the pool stays the same.

A somewhat gnarlier version for the math geeks out there:

A balance beam scale has 2 equal beakers of water, one on each side. Beakers are the same, water level's the same. All same-same so far.

One beaker has a golf-ball sized hollow sphere (of insignificant mass, so it floats) tethered to the bottom of the beaker on a thread (of insignificant mass) so it's suspended in the middle of the water.

The other beaker has an identically sized steel ball (so it sinks) suspended from the ceiling on a thread (of insignificant mass) so it's also suspended in the middle of the water.

Which one's heavier? That is, which side of the scale goes down?

(I was asked this question as part of my 9-hour entrance exam to work at the Evil Empire, so I had to answer in real-time, in front of my interrogator, after answering the above rock/boat/pool question...)

[mlydon]

The scale stays balanced - density of the spheres not a factor here.

Matt

[skipmac]

Originally Posted by Jon Hacking

Good answer. Since the floating rock is displacing its WEIGHT, not its volume, this is the same as when it was in the boat, so the water level of the pool stays the same.

A somewhat gnarlier version for the math geeks out there:

A balance beam scale has 2 equal beakers of water, one on each side. Beakers are the same, water level's the same. All same-same so far.

One beaker has a golf-ball sized hollow sphere (of insignificant mass, so it floats) tethered to the bottom of the beaker on a thread (of insignificant mass) so it's suspended in the middle of the water.

The other beaker has an identically sized steel ball (so it sinks) suspended from the ceiling on a thread (of insignificant mass) so it's also suspended in the middle of the water.

Which one's heavier? That is, which side of the scale goes down?

(I was asked this question as part of my 9-hour entrance exam to work at the Evil Empire, so I had to answer in real-time, in front of my interrogator, after answering the above rock/boat/pool question...)

I would say the scales are balanced.

Since the floating ball is of insignificant mass then it neither adds nor subtracts weight to that side. Floating is irrelevant since it is part of the system on that side of the scales with no outside connection or force acting on it.

Since the steel ball is fully supported by a connection outside the system then it does not add weight to the other side.

Since both balls are the same size and displace the same amount of water then the scales balance.

[StuM]

Originally Posted by skipmac

Since both balls are the same size and displace the same amount of water then the scales balance.

People tend to overthink the problem.
The answer would not change if the balls were differerent sizes
You've still got the same volume of water which is the only significant factor, as you identified:

Since the floating ball is of insignificant mass then it neither adds nor subtracts weight to that side. Floating is irrelevant since it is part of the system on that side of the scales with no outside connection or force acting on it.

Since the steel ball is fully supported by a connection outside the system then it does not add weight to the other side.

[skipmac]

Originally Posted by StuM

People tend to overthink the problem.
The answer would not change if the balls were differerent sizes
You've still got the same volume of water which is the only significant factor, as you identified:

Maybe I'm missing something but I don't follow that logic. The problem states that the water level is the same in each beaker.

So if the balls are not the same size, assume one ball is very tiny and one very large. If the water level is the same in both beakers then the beaker with the large ball will contain less water than the one with the tiny ball then the first beaker would weigh less.

[AKA-None]

Originally Posted by skipmac

Depends on the density of the rock. Heavy rock, IE density greater than water then the boat sitting lower displaces more water than the just rock so tossing the rock in the water the level goes down.



Density of the rock lighter than water then the rock will float. In that case I'll have to think about it more carefully but I think the water level would go up but might stay the same.

You do realize the rock was already in the water so pick it up and drop it back in there is no change

Sigh