Originally Posted by jkishel
No. With the haul at 90 degrees, the blocks will be 30 degrees off vertical and the tension will be 5.8 kg.
With T kg haul horizontal to the right, the horizontal reaction at the upper block will be T horizontal to the left. The 2T reaction at the upper block will therefore be 30 degrees off vertical. 2Tcos30 = 10 solving for T = 5.8kg.
The forces are:
Haul 5.8 to the right
Horizontal Reaction at upper block 5.8 to the left
Vertical reaction at upper block 10 up
Weight 10 down
Sum of the forces zero.
Had to go back to see where this came from - 2 parts
on the left, doh! concede - you are right. With a single
part each side the tension would approach infinity.