Originally Posted by sailronin
USCG tonnage has no relation to the "weight" of the vessel. You don't need to haul or weigh the boat.
Tonnage is determined by a formula based on internal volume of the boat, minus tankage volume. Each 40 cubic feet is one ton.
A rough guess is that your Cal 2-27 would be well under 10 tons.
LOL! I know that... in my original post I stated that I had already done a preliminary estimate by scaling the line drawing of the boat. And actually, it is LxDxB (in feet and 10ths) x .5 for a sailboat with fin keel
, x .9 for inboard engine
, / 100 so no, using the CG's Simplified Measurement System, it is not 40 cubic feet per ton. For my boat it is 45.
There were a lot of these boats built, and so I simply want to make sure that my claimed tonnage is in line with everybody else's who has documented their Cal 2-27 before I put in the application. As a life-long professional mariner, I have been filling out and submitting paperwork to the USCG for my entire adult life, and I have learned the importance of getting all the tees dotted and eyes crossed. And BTW, no, I have no plans to "weigh" my boat! The reason I need to haul it out is for a bottom job, and it will be my opportunity to take proper measurements, too.
Thanks everyone, for all the replies. I will just go with my measurements and call it good.