Originally Posted by Mike1956
Had another look at the calcs as follows...
53M x 1852 = 98,156m divided by 20m = 4,908 x 5 = 24,539 (inches) divide by 40 (+/- inches in a metre) = 613m
Chart would be 613m N to S
I will disagree, as a 5'' plotter in my book refers to the DIAGONAL not short side measure of a plotter.
I also keep my charts HORIZONTAL on my table and so I keep (most of the time) my plotter. I think depth
sounders and radars are often held in vertical orientation but plotters are more commonly found in the horizontal setup.
Here my take:
5'' screen is a DIAGONAL, how the hell do we know the height of the screen without knowing the ratio?
Basically though, for a 16:9 (+/- 2:1) screen:
- 5'' dia = 127 mm dia
- 127 mm dia at 2:1 ratio = 56.7 mm height,
Now, what is 53M. Do you want to say 53 Nm?
If so, then 53Nm x 1852m = 98156m / 20m = 4907.8 screen heights x 56.7mm / 1000 (mm to meter) = 278,27m
My paper chart would be 278,27 high. Mind I keep the plotter horizontal and so is my chart. Other assumptions will yield other results.
So my table would be only a quarter of your size?
Otherwise, we agree.
Let's synch up. Go thru my maths, I will go thru yours. We will find our bugs and agree on the table then.